-16(x)^2+60x=16

Solution for -16(x)^2+60x=16 equation:

-16(x)^2+60x=16

We move all terms to the left:

-16(x)^2+60x-(16)=0

a = -16; b = 60; c = -16;
Δ = b2-4ac
Δ = 602-4·(-16)·(-16)
Δ = 2576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2576}=\sqrt{16*161}=\sqrt{16}*\sqrt{161}=4\sqrt{161}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-4\sqrt{161}}{2*-16}=\frac{-60-4\sqrt{161}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+4\sqrt{161}}{2*-16}=\frac{-60+4\sqrt{161}}{-32}
$